Given : A={1,2,3},B={4},C={5},
Now,
B ∪ C={4}∪{5}
⇒ (B ∪ C={4,5}
A×(B ∪ C)={1,2,3}×{4,5}
⇒ A×(B ∪ C)={(1,4)(1,5),(2,4),(2,5),(3,4),(3,5)}
Also,
A × B={1,2,3}×{4}
⇒ A× B={(1,4),(2,4),(3,4)}
A × C={1,2,3}×{5}
⇒ A× C={(1,5),(2,5),(3,5)}
(A× B)∪(A× C)={(1,4),(2,4),(3,4)}
∪{(1,5),(2,5),(3,5)}
⇒(A× B)∪(A× C)={(1,4),(2,4),(3,4),(1,5),(2,5),(3,5)}
A×(B∪ C)=(A× B)∪(A× C)
Hence verfied