Given : A={1,2,3},B={4},{5}
Now, B ∩ C={4} ∩ {5}
⇒ B ∩ C=ϕ
A× (B ∩ C)={1,2,3}×ϕ
⇒ A× (B ∩ C)=ϕ
Also, ={1,2,3}×{4}
⇒ A× B{(1,4),(2,4),(3,4)}
⇒ A× C={(1,5),(2,5),(3,5)}
(A× B)∩ (A× C)={(1,4),(2,4),(3,4)}
∩{(1,5),(2,5),(3,5)}
⇒ (A× B)∩ (A× C)=ϕ
Hence verfied.