The correct option is
B N
A={1,3,5,7,9,11,13,15,17}
A′=N−A=N−{1,3,5,7,9,11,13,15,17}={2,4,6,8,10,12,14,16,18}
A∪B={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
B′=N−B=N−{2,4,6,8,10,12,14,16,18}={1,3,5,7,9,11,13,15,17}
(A∪B)∩B′
={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}∩{1,3,5,7,9,11,13,15,17}
={1,3,5,7,9,11,13,15,17}
A′∪((A∪B)∩B′)
={2,4,6,8,10,12,14,16,18}∪{1,3,5,7,9,11,13,15,17}
={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}=N