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Question

If A=[3 5] , B=[7 3] , then find a non-zero matrix C such that AC=BC


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Solution

Given two matrices are

A=[3 5] , B=[7 3]

To find out AC and BC, C must be a matrix of order 2×n where n is any natural number

[Number of rows of C must be equal to number of columns of A and B]

Taking n=1, Let C=[xy]

For AC=BC [ Given ]

[3 5][xy]=[7 3][xy]

[3x+5y]=[7x+3y]

Equating the corresponding element, we get

3x+5y=7x+3y

4x=2y

x=12y

y=2x

C=[x2x]

We can see clearly that on taking C of

order 2×1,2×2,2×3, … we get

C=[x2x],[xx2x2x],[xxx2x2x2x],……

Hence, in general

C=[k2k],[kk2k2k],etc,

Where k is any real number except zero .


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