If A=[3 5] , B=[7 3] , then find a non-zero matrix C such that AC=BC
Given two matrices are
A=[3 5] , B=[7 3]
To find out AC and BC, C must be a matrix of order 2×n where n is any natural number
[Number of rows of C must be equal to number of columns of A and B]
Taking n=1, Let C=[xy]
For AC=BC [ Given ]
⇒[3 5][xy]=[7 3][xy]
⇒[3x+5y]=[7x+3y]
Equating the corresponding element, we get
⇒3x+5y=7x+3y
⇒4x=2y
⇒x=12y
⇒y=2x
∴C=[x2x]
We can see clearly that on taking C of
order 2×1,2×2,2×3, … we get
C=[x2x],[xx2x2x],[xxx2x2x2x],……
Hence, in general
C=[k2k],[kk2k2k],etc,
Where k is any real number except zero .