Question

If $A=\{a,b,c\},B=\{c,d,e\},C\{a,d,f\},$ then $A\times (B\cup C)$ is

• A. $\left\{\right(a,d),(a,e),(a,c\left)\right\}$
• B. $\left\{\right(a,d),(b,d),(c,d\left)\right\}$
• C. $\left\{\right(d,a),(d,b),(d,c\left)\right\}$
• D. $noneofthese$

Answer 1

The correct option is D $noneofthese$

$\left(d\right)$.
$A\times (B\cup C)=\{a,b,c\}\times \{a,c,d,e,f\}$
The above set will consist of $15$ ordered pairs and not $3$.