If A- 2 2 -3 2 - B- 0 -1 1 0 - then B-1A-1-1-

The correct option is A [ 2 2 2 3 ] A=[ 2 amp; 2; 3 amp; 2 ], B=[ 0 amp; 1; 1 amp; 0 ] ( B ^ 1 A ^ 1 ) ...

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Evaluation of a Determinant

If A=[ 2 2...

Question

If $A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]$ then $(B^{- 1} A^{- 1})^{- 1} =$ ______

[\begin{matrix} 2 & - 2 2 & 3 \end{matrix}]

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[\begin{matrix} 2 & 2 - 2 & 3 \end{matrix}]

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[\begin{matrix} 2 & - 3 2 & 2 \end{matrix}]

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[\begin{matrix} 1 & - 1 - 2 & 3 \end{matrix}]

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A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}],

(B^{- 1} A^{- 1})^{- 1} =

A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}], B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}]

B^{- 1} A^{- 1}

A = [\begin{matrix} 2 & 2 - 3 & 2 \end{matrix}]

B = [\begin{matrix} 0 & - 1 1 & 0 \end{matrix}],

(B^{- 1} A^{- 1})^{- 1}

(1) 2² + 3²

(2) 3² − 2²

(3) 2² × 3³

(4) (−2)² × (1)²

(5) 1² + 5²

(6) 1² + 2⁰

(7) 7⁰ + 1²

(8) 6¹ − 4⁰

(9) 10⁰ − 2⁰

(10) 5¹× 3¹

t_{r} = \frac{1^{2} + 2^{2} + 3^{2} + . . . + r^{2}}{1^{3} + 2^{3} + . . . + r^{3}}

S_{n} = n \sum r = 1 {(- 1)}^{r} . t_{r},

lim n \to \infty S_{n} = \frac{2}{3}

1^{2} + 2^{2} + 3^{2} + . . . + r^{2} = \frac{r (r + 1) (2 r + 1)}{6}

1^{3} + 2^{3} + 3^{3} + . . . + r^{3} = {(\frac{r (r + 1)}{2})}^{2}

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