If A- cos- sin- -sin- sin- then A10-

The correct option is B ( cos 10α sin 10α sin 10α cos 10α) A = ( _ sinα^cosα _cosα^sinα) A^2 = ( _ sinα^cosα _cosα^sinα) ...

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Adjoint of a Matrix

If A= cosα ...

Question

If $A = (\begin{matrix} cos α & sin α - sin α & sin α \end{matrix})$ , then $A^{10} =$

(\begin{matrix} cos 10 α & - sin 10 α sin 10 α & cos 10 α \end{matrix})

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(\begin{matrix} cos 10 α & sin 10 α - sin 10 α & cos 10 α \end{matrix})

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(\begin{matrix} cos 10 α & - sin 10 α - sin 10 α & - cos 10 α \end{matrix})

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(\begin{matrix} - cos 10 α & - sin 10 α - sin 10 α & - cos 10 α \end{matrix})

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