Question

If $A=\left(\sin 0^o,\cos {90}^o\right),B=\left(\cos {30}^o,\sin {30}^o\right)$. Find the distance between ${}^{\prime }{A}^{\prime }$ and ${}^{\prime }{B}^{\prime }$

Answer 1

Given the points $A=\left(\sin 0^o,\cos {90}^o\right),B=\left(\cos {30}^o,\sin {30}^o\right)$ i.e. $A=(0,0),B=\left(\cos {30}^o,\sin {30}^o\right)$.

Now distance between $A$ and $B$ is

$\sqrt{{\sin }^2{30}^o+{\cos }^2{30}^o}$

$=\sqrt{1}$

$=1$.