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Question

If A={x:x25x+6=0} and B={y:yZ,3<|y2|5}, then the number of relations from A to B is

A
256.00
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B
256
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C
256.0
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Solution

A={x:x25x+6=0}
x25x+6=0
(x2)(x3)=0
x=2,3
A={2,3}

B={y:yZ,3<|y2|5}
3<|y2|5
Case :1 When y2
3<y25
5<y7

Case :2 When y<2
3<2y5
1<y3
3y<1

Since yZ,
y=3,2,6,7
B={3,2,6,7}

Number of relations from A to B is 2n(A)n(B)=224=256

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