If A- y-x2-y21-x- and B- y-x2-y2-4- x- then nA- B is

A= {y:x^2+y^21,x∈ℕ} We know that, y^2≥0, x^2≥1 ⇒ x^2 +y^2 ≥ 1 ⇒ A={ }=ϕ B= {y:x^2+y^2=4, x∈ℕ} y^2≥0, x^2≥1 ⇒ B= { √(3),0,√(3)} ∴ n(A× B)=0 ...

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Cartesian Product

If A= y:x2+y2...

Question

If $A = {y : x^{2} + y^{2} < 1, x \in N}$ and $B = {y : x^{2} + y^{2} = 4, x \in N},$ then $n (A \times B)$ is

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Similar questions

A = {y : x^{2} + y^{2} < 1, x \in N}

B = {y : x^{2} + y^{2} = 4, x \in N}

n (A \times B)

A = {(x, y) : x^{2} + y^{2} \leq 1; x, y ϵ R}

B = {(x, y) : x^{2} + y^{2} \geq 4; x, y ϵ R}

A = {(x, y) : x^{2} + y^{2} \leq 1; x, y \in R}

B = {(x, y) : x^{2} + y^{2} \geq 4; x, y \in R}

A = {(x, y) : x^{2} + y^{2} = 25}

B = {(x, y) : x^{2} + 9 y^{2} = 144}

A \cap B

If A = [(x,y): $x^{2} + y^{2} = 25$ ] And B = [(x,y): $x^{2} + 9 y^{2} = 144], t h e n A \cap B$ contains

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