'if a line is equally inclined to the axis then slope of line is plus or minus 1' but in first quadrant tan 45 is 1 so slope is 1 in third quadrant tan is positive so tan 45 is 1 when does minus one come?

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Solution

Dear Student,

$I n s e c o n d q u a d r a n t t h e s l o p e o f t h e l i n e i s \tan (90 + 45) ° = \tan 135 ° n o w \tan 135 c a n b e w r i t t e n a s \tan (180 - 45) \sin c e \tan (180 - θ) = - \tan θ h e n c e w e g e t \tan (180 - 45) = - \tan 45 = - 1 H e n c e i n s e c o n d q u a d r a n t t h e s l o p e o f l i n e i s - 1 . S i m i l a r l y i n 4 t h q u a d r a n t t h e s l o p e o f l i n e i s \tan (360 - 45) b u t \tan (360 - θ) = - \tan θ H e n c e i n 4 t h q u a d r a n t a l s o t h e s l o p e o f l i n e i s - 1 .$
Regards,

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