If a line L intersects three sides BC,CA and AB of △ABC in points P,Q and R then BPPC⋅CQQA⋅ARRB=.
In the given figure, the incircle of △ABC touches the sides AB, BC and CA at the points P, Q, R respectively. Show that AP+BQ+CR=BP+CQ+AR =12 (Perimeter of △ABC) [3 MARKS]