If a line L is a secant of a circle with centre c, then the perpendicular distance of the centre from L is less than the radius of the circle.

True

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False

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Solution

The correct option is A
True

We can see from the figure that $c p < r$

$\Rightarrow$ perpendicular distance of centre from the line is less than radius.

$\Rightarrow$ The given statement is true.

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Q. Assertion :STATEMENT - 1 : If a line

L = 0

is tangent to the circle

S = 0

, then it will also be a tangent to the circle

S + λ L = 0

. Reason: STATEMENT - 2 : If a line touches a circle, then perpendicular distance of the line from the centre of the circle is equal to the radius of the circle.

Statement 1: If a line $L = 0$ is tangent to the circle $S = 0$ , then it will also be a tangent to the circle $S + λ L = 0$

Statement 2: If a line touches a circle, then perpendicular distance of the line from the centre of the circle is equal to the radius of the circle.

In an equilateral $△$ ABC inscribed in a circle, the perpendicular bisector of BC & the angle bisector of angles B & C meet at the centre of the circle.

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If a line L is a secant of a circle with centre c, then the perpendicular distance of the centre from L is less than the radius of the circle.

The correct option is A True We can see from the figure that cp<r ⇒ perpendicular distance of centre from the line is less than radius. ⇒ The given statement is true.

The correct option is A
True

We can see from the figure that $c p < r$

$\Rightarrow$ perpendicular distance of centre from the line is less than radius.

$\Rightarrow$ The given statement is true.