If a line passes through the points (2, 5) and (-1, -1), equation of the line is .
A
3x−2y+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2x−y−1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2x−y+1=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is C2x−y+1=0 Given: Points (2, 5) and (-1, -1)
We know that the slope of the line passing through the points (x1,y1) and (x2,y2) is y2−y1x2−x1.
So, slope of the line(m) = −1−5−1−2
Slope of the line(m) = −6−3
Slope of the line(m) = 2
Equation of the line: y−y1=m(x−x1)
Equation of the line: y−5=2(x−2)
Equation of the line: y−5=2x−4
Equation of the line: 2x−y+1=0