If a line with direction ratio 2-2-1 intersects the line x-73-y-52-z-31 and x-12-y-14-z-13 at A and B then AB-

The correct option is C 3 units [ x 7 / 3 = y 5 / 2 = z 3 / 1 Let A=( 3 r_ 1 +7, 2 r_ 1 +5, r_ 1 +3 ) ...

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Angle between Two Line Segments

If a line wit...

Question

If a line with direction ratio $2 : 2 : 1$ intersects the line $\frac{x - 7}{3} = \frac{y - 5}{2} = \frac{z - 3}{1}$ and $\frac{x - 1}{2} = \frac{y + 1}{4} = \frac{z + 1}{3}$ at $A$ and $B$ then $A B =$

\sqrt{2} u n i t s

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2 u n i t s

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\sqrt{3} u n i t s

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3 u n i t s

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Solution

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Similar questions

(2, 2, 1)

\frac{x - 7}{3} = \frac{y - 5}{2} = \frac{z + 3}{1}

\frac{x - 1}{2} = \frac{y + 1}{4} = \frac{z + 1}{3}

2 : 2 : 1

\frac{x - 7}{3} = \frac{y - 5}{2} = \frac{z - 3}{1}

\frac{x - 1}{2} = \frac{y + 1}{4} = \frac{x + 1}{3}

A

B

A B =

Δ A B C, ∠ B = 90^{0}, A B = y u n i t s, B C = \sqrt{3} u n i t s, A C = 2 u n i t s

A = x^{0}

y

Δ A B C, ∠ B = 90^{0}, A B = y u n i t s, B C = \sqrt{3} u n i t s, A C = 2 u n i t s

A = x^{0}

sin x^{0}

\frac{\sqrt{3}}{m}

\frac{x - 1}{2} = \frac{y + 1}{3} = \frac{z - 1}{4}

\frac{x - 3}{1} = \frac{y - k}{2} = \frac{z}{1}

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