If a linear equation has solutions (2,−2),(0,0) and (−2,2), then it is of the form
A
y−x=0
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B
x+y=0
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C
2x+y=0
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D
x+2y=0
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Solution
The correct option is Bx+y=0 Let the linear equation be y=ax+b ...(1) By substituting (x,y)=(0,0) in the equation, we get, 0=0x+b⇒b=0 Now, our equation becomes y=ax (Since b=0) ...(2) By substituting (x,y)=(2,−2)in the equation, we get −2=2a⇒a=−1 ∴ Final equation becomes y=−x or x+y=0 Hence, option B.