If $a = l o g_{24} 12, b = l o g_{36} 24, c = l o g_{48} 36$ , then 1 + abc is equal to

2 ac

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 bc

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 ab

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 2 bc
$a b c = \frac{l o g 12}{l o g 24} . \frac{l o g 24}{l o g 36} . \frac{l o g 36}{l o g 48} = \frac{l o g 12}{l o g 48}$
$∴ 1 + a b c = \frac{l o g 48 + l o g 12}{l o g 48} = \frac{l o g (48.12)}{l o g 48}$
$= \frac{l o g 24^{2}}{l o g 48} = 2. \frac{l o g 24}{l o g 48} = 2 b c$

Suggest Corrections

Similar questions

a = l o g_{24} 12, b = l o g_{36} 24 a n d c = l o g_{48} 36

x = {log}_{24} 12, y = {log}_{36} 24

z = {log}_{144} 36

1 + 2 x y z

f $a = {log}_{24} 12, b = {log}_{36} 24, c = {log}_{48} 36$ , then 1+abc is equal to ______________.

a = l o g_{24} 12, b = l o g_{36} 24 a n d c = l o g_{48} 36

a = l o g_{24} 12, b = l o g_{36} 24 a n d c = l o g_{48} 36

Join BYJU'S Learning Program