Question

If $a\log x-b\log y=2\log 3$ is $x^a=m{y}^b$, then value of $m$ is equal to

• A. $1$
• B. $2$
• C. $8$
• D. $9$

Answer 1

Answer: (D)

$9$

$a\log x-b\log y=2\log 3\log x^a=2\log 3+\log y^b\log x^a=\log 9y^b\text{Removing log}{x}^a=9y^b$

$\Rightarrow m=9$