If a<0 and D<0, then the graph of y=ax2+bx+c (where D=b2−4ac)
A
lies entirely above x−axis
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B
lies entirely below x−axis
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C
cuts the x−axis
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D
touches the x−axis
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Solution
The correct option is B lies entirely below x−axis For the equation y=ax2+bx+c a<0⇒ downward opening parabola Given b2−4ac<0 ⇒D<0⇒ no real roots The graph of y=ax2+bx+c lies entirely below the x−axis