If $a^{m} = a^{n}$ then find the value of $m - n$ .

Open in App

Solution

Given,
$a^{m} = a^{n}$
or, $a^{m - n} = 1$
or, $a^{m - n} = a^{0}$ .
Then $m - n = 0$ .

Suggest Corrections

Similar questions

m - n

a^{m} = a^{n}

If $a^{m}$ × $a^{n}$ = $a^{x}$ , then the value of $x$ is _____. (where m and n are natural numbers)

M = a (m + n)

N = b (m - n)

(\frac{M}{a} + \frac{N}{b}) \div (\frac{M}{a} - \frac{N}{b})

A_{i} = \frac{x - a_{i}}{| x - a_{i} |}, i = 1, 2, . . . . ., n,

a_{1} < a_{2} < a_{3} < . . . . . < a_{n} .

1 \leq m \leq n, m \in N,

R = lim x \to a_{m}^{+} (A_{1} A_{2} . . . . A_{n})

\frac{a^{n + 1} + b^{n + 1}}{a^{n} + b^{n}}

Join BYJU'S Learning Program