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Question

If A.M. of b and c is a and the two geometric means between them are G1 and G2, then the value of G31+G32 is

A
abc
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B
2abc
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C
3abc
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D
4abc
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Solution

The correct option is B 2abc
Given : A.M. of b and c is a, so
2a=b+c

Now, b,G1,G2,c are in G.P., so
br3=cr=(cb)1/3

Therefore,
G1=br, G2=br2G31+G32=b3r3(1+r3)G31+G32=b2c[1+cb]G31+G32=bc(b+c)G31+G32=2abc

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