If a machine overcomes a load $L$ and the distance travelled by the load is $L_{d}$ . Similarly, the effort applied in the machine is $E$ and the distance travelled by effort is $E_{d}$ , and $^{'} T^{'}$ is the time taken then velocity ratio can be written as

\frac{E_{d}}{L_{d}}

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\frac{L_{d}}{E_{d}}

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\frac{E_{d}}{\sqrt{L_{d}}}

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\frac{\sqrt{L_{d}}}{E_{d}}

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Solution

The correct option is A $\frac{E_{d}}{L_{d}}$
The VR is define as ratio of distance travelled by effort:distance travelled by load

$V R = \frac{E_{d}}{L_{d}}$

option A is correct.

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Similar questions

L

25 m

E

75 m

^{'} T^{'}

Mechanical advantage (M. A), load (L) and effort (E) are related as :

(a) M.A = L $\times$ E (b) M.A. $\times$ E = L

Determine the required velocity ratio for a machine whose effort distance is 3 times that of load distance.

In a quadrilateral ABCD,LA=150 and LB=LC=LD,f finLB,LC, AND LD

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