If a magnet of pole strength m is divided into four parts such that the length and width of each part is half that of initial one, then the pole strength of each part will be

\frac{m}{4}

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\frac{m}{2}

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\frac{m}{8}

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4 m

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Solution

The correct option is B $\frac{m}{2}$

For each part $m^{'} = \frac{m}{2}$

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If a magnet of pole strength m is divided into four parts such that the length and width of each part is half that of initial one, then the pole strength of each part will be

The correct option is B m2 For each part m′=m2

The correct option is B $\frac{m}{2}$

For each part $m^{'} = \frac{m}{2}$