If a magnification of, –1 (minus 1) is obtained by using a converging lens, then the object has to be placed:
(a) within f
(b) at 2f
(c) beyond 2f
(d) at infinity
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Solution
(b) At 2f
When an object is placed at 2f, the size of the image formed will be equal to the size of the object. Therefore, we get a magnification of 1.