If a man of mass M jumps to the ground from a height h and his centre of mass moves a distance x in the time taken by him to 'hit' the ground, and the average force acting on him (assuming his retardation to be constant during his impact with the ground) is

M g h / x

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M g x / h

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M g (h / x)^{2}

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M g (x / h)^{2}

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Solution

The correct option is A $M g h / x$
As the centre of mass moves through a distance x, the averge force F acting on the man is calculate from :
Work done = Change in potential energy
Fx=Mgh
F=Mgh/x Hence Option A is the right answer.

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If a man of mass M jumps to the ground from a height h and his centre of mass moves a distance x in the time taken by him to 'hit' the ground, and the average force acting on him (assuming his retardation to be constant during his impact with the ground) is

The correct option is A Mgh/xAs the centre of mass moves through a distance xx, the averge force FF acting on the man is calculate from :Work done = Change in potential energyFx=MghFx=MghF=Mgh/x Hence Option A is the right answer.

The correct option is A $M g h / x$
As the centre of mass moves through a distance x, the averge force F acting on the man is calculate from :
Work done = Change in potential energy
Fx=Mgh
F=Mgh/x Hence Option A is the right answer.