If a matrix $P$ has $8$ elements, then how many different values the order of the matrix can take?

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Solution

The correct option is B $4$
A matrix of $m$ rows and $n$ columns has $m \times n$ elements.
$8$ can be got by all combinations of $1 \times 8, 8 \times 1, 2 \times 4, 4 \times 2$
Hence, there are $4$ possible matrices which have $8$ elements.

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Similar questions

If a matrix has 8 elements, how many possible orders can it have?

Identify the correct statements:

(i) A matrix with 3 columns and 2 rows is of order $3 \times 2$ .
(ii) A matrix with 5 columns and 8 rows is of order $8 \times 5$
(iii) If the order of a matrix is $4 \times 3$ , then it has 12 elements.
(iv) If the order of a matrix is $5 \times 3$ , then it has 10 elements.

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Q. If a matrix has 8 elements, what are the possible number of orders it can have?

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If a matrix P has 8 elements, then how many different values the order of the matrix can take?

The correct option is B 4A matrix of m rows and n columns has m×n elements. 8 can be got by all combinations of 1×8,8×1,2×4,4×2 Hence, there are 4 possible matrices which have 8 elements.

If a matrix $P$ has $8$ elements, then how many different values the order of the matrix can take?

The correct option is B $4$
A matrix of $m$ rows and $n$ columns has $m \times n$ elements.
$8$ can be got by all combinations of $1 \times 8, 8 \times 1, 2 \times 4, 4 \times 2$
Hence, there are $4$ possible matrices which have $8$ elements.