Question

If a metal ion is less easily reduced than a hydrogen ion, the electrolysis of an aqueous solution of its salt:

• A. liberates hydrogen gas at the anode
• B. liberates hydrogen gas at the cathode
• C. produce the metal at either electrode
• D. produces oxygen at the anode

Answer 1

The correct option is B liberates hydrogen gas at the cathode

Element with a higher reduction potential gets reduced at the cathode.

$\because H^{+}$ is more easily reduced.

$\therefore$ At cathode: $2H^{+}+2e^{-}\to H_2$

$H_2$ is liberated.

Option B is correct.