Question

If a metal react with 48g of oxygen to give 102g of oxide of the metal then equivalent weight of the metal is

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Equivalent}\mathrm{weight}\mathrm{of}\mathrm{metal}=\frac{\mathrm{Weight}\mathrm{of}\mathrm{metal}}{\mathrm{Weight}\mathrm{of}\mathrm{oxygen}\mathrm{combined}}\times 8 \\ =\frac{102-48}{48}\times 8 \\ =\frac{54}{48}\times 8 \\ =\frac{54}{6} \\ =9\mathrm{g}{\mathrm{eq}}^{-1} \end{gathered}$$