If a metallic cuboid weighs 16 kg, what would be the weight of the new cuboid of metal, if all dimensions are reduced to one – fourth of the original?
0.25 kg
Let the dimensions of the bigger cuboid be x, y and z
Then, volume of the bigger cuboid = xyz.
Volume of the miniature cuboid =(14x)(14y)(14z)=164xyz
∴Weight of the miniature cuboid = (164×16)kg=0.25kg