Question

If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, then the ratio of initial and final volume under same temperature and pressure would be :

• A. 3 : 1
• B. 1 : 3
• C. 2 : 1
• D. 1 : 2

Answer 1

The correct option is C 2 : 1

The reaction for conversion is

$N_2+{3H}_2\to {2NH}_3$

Here, $n_1=3+1=4n_2=2Initialvolume=V_{1}FinalVolume=V_2$

Applying Avagadro's Law, we get

$\frac{V_1}{n_1}=\frac{V_2}{n_2}\frac{V_1}{V_2}=\frac{n_1}{n_2}\frac{V_1}{V_2}=\frac{4}{2}=\frac{2}{1}$

So,$V_1:V_2=2:1$.

So, correct answer is option $C$.