If a monoatomic gas is suddenly compressed to 18 of its volume adiabatically- then the pressure of the gas is

The correct option is D 32 times the initialIn an adiabatic process we have P × V^γ constant . γ for monoatomic is 5/3. #160;Therefore for V to b ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Thermodynamic Processes

If a monoatom...

Question

If a monoatomic gas is suddenly compressed to $\frac{1}{8}$ of its volume adiabatically, then the pressure of the gas is

8 times the initial

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16 times the initial

No worries! We‘ve got your back. Try BYJU‘S free classes today!

32 times the initial

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

128 times the initial

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 32 times the initial
In an adiabatic process we have $P \times V^{γ}$ constant .
$γ$ for monoatomic is 5/3.
Therefore for V to become 1/8 of the original volume .
Substituting values in the equation will give final pressure to be 32P.

Suggest Corrections

Similar questions

A monoatomic gas $(γ = \frac{5}{3})$ is suddenly compressed to $\frac{1}{8}$ of its original volume adiabatically, then the pressure of the gas will change to.

Q. A monoatomic ideal gas at pressure

P_{0}

is suddenly compressed to

\frac{1}{27}

its initial volume. The final pressure will be:

Q. An ideal monoatomic gas at

27^{\circ} C

is compressed adiabatically to

8 / 27

times of its present volume. The increase in temperature of the gas is:

Q. A diatomic gas

(γ = \frac{7}{5})

is compressed to

\frac{1}{32}

times of its initial volume adiabatically and reversibly. If its initial pressure is

2 P_{0}

, its new pressure will be :

Q. A gas has pressure P and volume V. It is now compressed adiabatically to

\frac{1}{32}

times the original volume. Given that

(32)^{1.4} = 128

, the final pressure is (

γ = 1.4

)

Join BYJU'S Learning Program

If a monoatomic gas is suddenly compressed to 18 of its volume adiabatically, then the pressure of the gas is

The correct option is D 32 times the initialIn an adiabatic process we have P×Vγ constant .γ for monoatomic is 5/3. Therefore for V to become 1/8 of the original volume .Substituting values in the equation will give final pressure to be 32P.

If a monoatomic gas is suddenly compressed to $\frac{1}{8}$ of its volume adiabatically, then the pressure of the gas is

The correct option is D 32 times the initial
In an adiabatic process we have $P \times V^{γ}$ constant .
$γ$ for monoatomic is 5/3.
Therefore for V to become 1/8 of the original volume .
Substituting values in the equation will give final pressure to be 32P.