If a monoatomic gas is suddenly compressed to 18 of its volume adiabatically- then the pressure of the gas is

The correct option is D 32 times the initialIn an adiabatic process we have P × V^γ constant . γ for monoatomic is 5/3. #160;Therefore for V to b ...

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Standard XII

Physics

Thermodynamic Processes

If a monoatom...

Question

If a monoatomic gas is suddenly compressed to $\frac{1}{8}$ of its volume adiabatically, then the pressure of the gas is

8 times the initial

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16 times the initial

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32 times the initial

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128 times the initial

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Solution

The correct option is D 32 times the initial
In an adiabatic process we have $P \times V^{γ}$ constant .
$γ$ for monoatomic is 5/3.
Therefore for V to become 1/8 of the original volume .
Substituting values in the equation will give final pressure to be 32P.

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If a monoatomic gas is suddenly compressed to 18 of its volume adiabatically, then the pressure of the gas is

The correct option is D 32 times the initialIn an adiabatic process we have P×Vγ constant .γ for monoatomic is 5/3. Therefore for V to become 1/8 of the original volume .Substituting values in the equation will give final pressure to be 32P.

If a monoatomic gas is suddenly compressed to $\frac{1}{8}$ of its volume adiabatically, then the pressure of the gas is

The correct option is D 32 times the initial
In an adiabatic process we have $P \times V^{γ}$ constant .
$γ$ for monoatomic is 5/3.
Therefore for V to become 1/8 of the original volume .
Substituting values in the equation will give final pressure to be 32P.