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Question

If a N={ax;xϵN}, description of the set 3N7N is 3kN .Find k ?

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Solution

aN={an:nN}={a,2a,3a,4a,...}
3N={3,6,9,12,15,18,21,24,27,30,...} and 7N={7,14,21,28,35,42,...}
3N7N={21,42,63,84,...}={1×21,2×21,3×21,4×21,...}={21n:nN}
3kN=21N
k=7

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