IF an denotes the nth term of the AP 2, 7, 12, 17, ..., find the value of (a30−a20).
We have a = 2 ; d = 5
now, a30=a+(30−1)d=2+29×5=2+145=147
a20=a+19d=2+19×5=2+95=97
now, a30−a20=147−97=50
If an denotes the nth term of the AP 3, 8, 13, 18, ... then what is the value of (a30−a20) (a) 40 (b) 36 S(c) 50 (d) 56