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Question

If an is a sequence such that a1=1, a2=1+a1, a3=1+a1a2, an+1=1+a1a2a3......an then find the value of 1a1+1a2+1a3+1a4.....

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Solution

a1=1,a2=1+a1=2a3=1+a1a2=3,a4=1+a1a2a3=7an+1=1+a1a2....an=1+(an1)an(an=1+a1a2....an1)an+1=a2nan+1an+11=a2nan1an+11=1a2nan1an+11=1an11an1an=1an11an+111a1+1a2+1a3+1a4+....+1an+..=1a1+1a2+1a3+(1a411a51)+(1a511a61)+...+(1an11an+11)=1a1+1a2+1a3+1a41=1+12+13+16=21a1+1a2+1a3+....+1an+...=2

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