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Question

If a.N={ax:xN} then 3N7N=

A
21 N
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B
10 N
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C
4 N
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D
none
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Solution

The correct option is A 21 N
Clearly the set aN will include all multiples of a.

Hence 3N and 7N contain multiples of 3 and 7 respectively.

Their intersection must have the multiples of their L.C.M,i.e,21

Hence 3N7N=21N

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