If a natural number 'n' is a perfect square, then its square root is a ___ number.

decimal

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natural

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integer

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negative

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Solution

The correct option is A
decimal

If a natural number 'n' can be expressed as $m^{2}$ , where 'm' is a natural number, then 'n' is a square number.

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If a number is both perfect square and perfect cube, then it will have a sixth root which is a natural number.

Prove that x² − 6x + 9 is a perfect square for all natural numbers x. What can you say about its square root?

n

n + 2 n + 3 n + . . . . . + 99 n

n^{2}

n

n + 2 n + 3 n + \dots + 99 n

n^{2}

ρ

ρ

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