CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If ap,bq,cr and ∣ ∣pbcp+aq+b2cabr∣ ∣=0, then ppq+qqb+rrc=
  1. 3
  2. 2
  3. 1
  4. 0


Solution

The correct option is B 2
∣ ∣pbcp+aq+b2cabr∣ ∣=0 Applying R2R2R1
=∣ ∣pbcaqcabr∣ ∣=0
Applying R2R2R1 and R3R3R1
=∣ ∣pbcapqb0ap0rc∣ ∣=0
On expansion we get,
p(qb)(rc)b(ap)(rc)c(qb)(ap)=0(pa)(qb)(rc)[p(pa)+b(qb)+c(rc)]=0(pa)(qb)(rc)[p(pa)+q(qb)1+r(rc)1]=0pa,qb,rcppa+qqb+rrc=2.

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


People also searched for
View More



footer-image