Question

If a number is divisible by $2$ and $3$, then it satisfies the divisibility rule of?

Answer 1

Compute the divisibility rule:

$6$ can be factorized as,

$6=2\times 3$

Hence the only two factors $6$ has are $2$ and $3$.

So, whenever a number is divisible by both $2$ and $3$ it will have $6$ as a factor and will consequently be divisible by $6$.

For example:

$96=\left(2\times 3\right)\times 2^4=6\times 2^4$

$96$ is a number that is divisible by $2$ and $3$.

Therefore, it is also divisible by $6$.

Hence, the divisibility rule of $6$ is satisfied by the numbers $2$ and $3$.