If a number is divisible by 9, then it is also divisible by ___

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Solution

Let the number A be divisible by 9.
So, the remainder when A is divided by 9 is 0.
$D i v i d e n d = (d i v i s o r \times q u o t i e n t) + r e m a i n d e r$
So, $A = 9 \times B + 0 = 9 \times B$
$A = 9 \times B = 3 \times 3 \times B = 3 \times 3 B = 3 \times C (C = 3 \times B)$
So, A is also divisible by 3 because 3 is factor of 9.
But if A is divisible by 3 it need not be divisible by 9.

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Similar questions

9

Which of the following statements are true?

(a) If a number is divisible by 3, it must be divisible by 9.

(b) If a number is divisible by 9, it must be divisible by 3.

(d) If a number is divisible by 9 and 10 both, then it must be divisible by 90.

(e) If two numbers are co-primes, at least one of them must be prime.

(f) All numbers which are divisible by 4 must also be divisible by 8.

(g) All numbers which are divisible by 8 must also be divisible by 4.

(h) If a number exactly divides two numbers separately, it must exactly divide their sum.

(i) If a number exactly divides the sum of two numbers, it must exactly divide the two numbers separately.

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