If a number is divisible by both 2 and 3, it is also divisible by ___.

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Solution

The correct option is A
6

If a number P is divisible by 2 and 3, then it can be written in form:
$P = 2 \times 3 \times a \times b \times . . . . . . . .$
$P = 6 \times a \times b \times . . . . . . . . .$

$\frac{P}{6}$ = $a \times b \times . . . . . . . .$

$D i v i d e n d = (D i v i s o r \times Q u o t i e n t) + R e m a i n d e r$

Here, Remainder = 0, when P is divided by 6.

So, it is divisible by 6 also.

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18 is divisible by both 2 and 3. It is also divisible by $2 \times 3 = 6.$ Similarly, a number is divisible by 4 and 6. Can we say that the number must be divisible by $4 \times 6 = 24 ?$ If not, give an example to justify your answer.

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If a number is divisible by both 2 and 3, it is also divisible by ___.

The correct option is A 6 If a number P is divisible by 2 and 3, then it can be written in form: P=2×3×a×b×........ P=6×a×b×......... P6 = a×b×........ Dividend=(Divisor×Quotient)+Remainder Here, Remainder = 0, when P is divided by 6. So, it is divisible by 6 also.