Question

If a number is exactly divisible by both $2$ and $7$, then number is exactly divisible by

• A. $11$
• B. $12$
• C. $13$
• D. $14$

Answer 1

The correct option is D $14$

If a number is exactly divisible by both $2$ and $7$, then number is exactly divisible by $14$.
Example: $728$
The last digit is even, so $728$ is divisible by $2$.
$728$ is multiple of $7$, so it is divisible by $7$.
Therefore, $728$ is divisible by $14$.