If a number of capacitors of equal capacity C each are arranged as shown, the equivalent capacity is given by :
A
n2(n+1)2C
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B
(2n+1)C
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C
(n−1)n2C
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D
(n+1)n2C
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Solution
The correct option is D(n+1)n2C The capacitors in the each loop are in parallel and then they are also in parallel. The equivalent circuit is shown in figure below. Ceq=C+2C+3C+4C+.......+nC Ceq=C(1+2+3+4+......+n)=C[n(n+1)2]