False
Given that PQ is any line segment and
S1,S2,S3,S4……… circles are touch a line segment PQ at a point A .
Let the centres of the circles
S1,S2,S3,S4 ………..be
C1,C2,C3,C4 …….respectively.
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/175871/content_220426.png)
To Prove: Centres of these circles lie on the perpendicular bisector of PQ.
Now, joining each centre of the circles to the point A on the line segment PQ by a line segment .i.e
C1A,C2A,C3A,C4A...... so on.
We know that, if we draw a line from the centre of a circle to its tangent line, then the line is always perpendicular to the tangent line, But it does not bisect the line segment PQ.
C1A⊥PQ[For S1]C2A⊥PQ[For S2]C3A⊥PQ[For S3]C4A⊥PQ[For S4] Since, each circle is passing through a point A . therefore, all the line segments
C1A,C2A,C3A,C4A......, so on.
So, the centre of each circle lies on the perpendicular line of PQ but they do not lie on the perpendicular bisector of PQ.
Hence, a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular of PQ but not on the perpendicular bisector of PQ.