Question

If a number which is less than its square by 42 then sum of the possible values of the numbers is

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is A 1

Let the number be $x$
Given, $x^2-x=42$
$=>x^2-x-42=0$
$=>x^2-7x+6x-42=0$
$=>x(x-7)+6(x-7)=0$
$=>(x+6)(x-7)=0$
$=>x=-6,7$
And sum of these values $=-6+7=1$