Question

If a number x is chosen from the numbers 1, 2, 3, and a number y is selected from the numbers 1, 4, 9. Then, P(xy < 9)

(a) $\frac{7}{9}$

(b) $\frac{5}{9}$

(c) $\frac{2}{3}$

(d) $\frac{1}{9}$

Answer 1

GIVEN: x is chosen from the numbers 1, 2, 3 and y is chosen from the numbers 1, 4, 9

TO FIND: Probability of getting

We will make multiplication table for x and y such that

So the numbers such that is 5

We know that PROBABILITY =

Hence

Hence the correct option is