If a nut can be opened with a minimum force of $6 N$ using a wrench of length $12 c m$ , what is the moment of force needed to turn the nut?

0.72 N m^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.72 N m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50 N m^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

72 N m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.72 N m$
Moment of force = Force x Perpendicular distance from the axis of rotation
$= 6 N \times 12 c m = 6 N \times 0.12 m = 0.72 m$ .
Therefore, the moment of force required to turn the nut $= 0.72 N m$ .

Suggest Corrections

Similar questions

Q. A nut is opened by a wrench of length

10 c m

. If the least force required is

5.0 N

, find the moment of force needed to turn the nut.

A spanner of length 10cm is used to open a nut by applying a minimum force of 0.5N.calculate the moment of force required.

Q. A nut just opens by applying a force of 150 N using a wrench of length 30 cm. If we wants to open it by a force of 50 N then the length of wrench should be:

When a force of 6.0 N is exerted at 30 $^{\circ}$ to a wrench at a distance of 8 cm from the nut, it is just able to loosen the nut. What force F would be sufficient to loosen it if it acts perpendicularly to the wrench at 16 cm from the nut ?

Join BYJU'S Learning Program

If a nut can be opened with a minimum force of 6 N using a wrench of length 12 cm, what is the moment of force needed to turn the nut?

The correct option is B 0.72 N mMoment of force = Force x Perpendicular distance from the axis of rotation =6 N×12 cm=6 N×0.12 m=0.72 m. Therefore, the moment of force required to turn the nut =0.72 Nm.

If a nut can be opened with a minimum force of $6 N$ using a wrench of length $12 c m$ , what is the moment of force needed to turn the nut?

The correct option is B $0.72 N m$
Moment of force = Force x Perpendicular distance from the axis of rotation
$= 6 N \times 12 c m = 6 N \times 0.12 m = 0.72 m$ .
Therefore, the moment of force required to turn the nut $= 0.72 N m$ .