If a pair of linear equation $a_{1} x + b_{1} y + c_{1} = 0$ and $a_{2} x + b_{2} y + c_{2} = 0$ represents coincident lines, then

\frac{a 1}{a 2} \neq \frac{b 1}{b 2}

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\frac{a 1}{a 2} = \frac{b 1}{b 2} \neq \frac{c 1}{x 2}

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\frac{a 1}{a 2} = \frac{b 1}{b 2} = \frac{c 1}{c 2}

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\frac{a 1}{a 2} = \frac{a 2}{b 2}

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Solution

The correct option is C $\frac{a 1}{a 2} = \frac{b 1}{b 2} = \frac{c 1}{c 2}$
For co-incident lines
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$

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If a pair of linear equation a1x+b1y+c1=0 and a2x+b2y+c2=0 represents coincident lines, then

The correct option is C a1a2=b1b2=c1c2For co-incident lines a1a2=b1b2=c1c2

If a pair of linear equation $a_{1} x + b_{1} y + c_{1} = 0$ and $a_{2} x + b_{2} y + c_{2} = 0$ represents coincident lines, then

The correct option is C $\frac{a 1}{a 2} = \frac{b 1}{b 2} = \frac{c 1}{c 2}$
For co-incident lines
$\frac{a_{1}}{a_{2}} = \frac{b_{1}}{b_{2}} = \frac{c_{1}}{c_{2}}$