If a parabolic reflector is 20 cm in diameter and 5 cm deep, the focus of the reflector is
A
(0,5)
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B
(0,0)
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C
(5,0)
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D
(5,5)
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Solution
The correct option is C(5,0) Taking vertex of the parabola reflector of origin, x-axis along the axis of the parabola the equation of a parabola is y2=4ax. Given depth 5cm diameter 20cm
∴(5,10) point lies on a parabola.
∴a=5
∴ Focus is (a,0), i.e. (5,0) which is mid-point of the given diameter