If a particle is moving from its initial position x=−5m to a position x=−11m in 2s along a straight line. What will be the average velocity of particle ?
A
5m/s
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B
−3m/s
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C
3m/s
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D
−6m/s
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Solution
The correct option is B−3m/s Displacement is the difference of final and initial position. ⇒Δx=xf−xi ⇒Δx=−11−(−5)=−6m
Hence average velocity is, Velocityavg=ΔxΔt ⇒Velocityavg=−62 ∴Velocityavg=−3m/s
The negative sign of average velocity indicates that particle is moving along −vex−axis.