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Horizontal and Vertical Components of Projectile Motion

If a particle...

Question

If a particle is projected at t=0 from ground with speed u= 20 m/s at an angle of 45^° from horizontal then find the ratio of time of flight to the time interval in which velocity of particle becomes perpendicular to initial velocity of projection -

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Q. A particle is projected from the ground with an initial velocity of

20 m / s

30^{\circ}

with horizontal. The magnitude of change in velocity in a time interval from

t = 0

t = 0.5 s

(g = 10 m / s^{2})

Q. A particle is projected from the ground with an initial velocity of

20

m/s at an angle of

30^{o}

with horizontal. The magnitude of change in velocity in a time interval from

t = 0

t = 0.5

(g = 10 m / s^{2})

Q. A particle is projected from ground at angle

45^{\circ}

with initial velocity

20 \sqrt{2} m / s .

Find magnitude of average velocity in a time interval from

t = 0

t = 3 s

. Round off to the nearest integer.

Q. A particle is projected from ground with speed 80 m/s at an angle

30^{0}

with horizontal from ground. The magnitude of average velocity of particle in time interval t = 2 s to t = 6 s is [Take g = 10

m / s^{2}

Q. A particle is projected from the ground at an angle of

θ

with the horizontal with an initial speed of

u

. Time after which velocity vector of the projectile is perpendicular to the initial velocity is

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Horizontal and Vertical Components of Projectile Motion

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